20CN网络安全小组论坛 - 编程破解 - 一个扫描器（source）

论坛: 编程破解标题: 一个扫描器（source）

作者: quest [quest]

版主

[CODE]
/*该程序用到了pthread库，编译时记得加上，不然无法通过.
*还有很多东西，本来想做的，没时间了...:(（其实是懒）
*/
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdarg.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netdb.h>
#include <pthread.h> //多线程库

int port;
int sockfd, net, j = 0;
struct sockaddr_in sa;
struct hostent *host;
char *hostname;
pthread_mutex_t mutex;
void scan (void *tID);

int main (int argc, char *argv[])
{
int iCount, i;
int iResult;
char c;
pthread_t tScan[100];

if (argc < 2)
{
printf ("Usage:%s hostname\n", argv[0]);
exit (1);
}
strncpy ((char *) &sa, "", sizeof sa);
sa.sin_family = AF_INET;
if (isdigit (*argv[1]))
{
sa.sin_addr.s_addr = inet_addr (argv[1]);
hostname = argv[1];
}
else if ((host = gethostbyname (argv[1])) != 0)
{
strncpy ((char *) &sa.sin_addr, (char *) host->h_addr,
sizeof sa.sin_addr);
}
else
{
herror (argv[1]);
exit (2);
}
pthread_mutex_init (&mutex, NULL);
iCount = atoi (argv[2]);
printf ("%d\n", iCount);
port = 0;
for (i = 0; i < iCount; i++)
{
iResult = pthread_create (&tScan[i], NULL, (void *) &scan, (void *) i);
}
for (i = 0; i < iCount; i++)
pthread_join(tScan[i], NULL);
if (j == 0)
printf ("You hava no port to open the System maybe safe!\n");
else
printf ("There are %d port opened!\n", j);
printf ("\r");
fflush (stdout);
return (0);
}

int getport ()
{
return (++port > 65535 ? -1 : port);
}

void scan (void *tID)
{
int iPort;
int iTID;
iTID = (int) tID;
iPort = 0;
while (iPort != -1)
{
pthread_mutex_lock (&mutex);
iPort = getport ();
pthread_mutex_unlock (&mutex);
if (iPort == -1)
return;
sa.sin_port = htons (iPort);
sockfd = socket (AF_INET, SOCK_STREAM, 0);
if (sockfd < 0)
{
perror ("\nsocket");
}
net = connect (sockfd, (struct sockaddr *) &sa, sizeof sa);
if (net < 0)
{
}
else
{
j++;
printf ("thread %d get port %d\n", iTID, iPort);
printf ("%s %d accepted.\n", hostname, iPort);
}
close (sockfd);
}
}

[此贴被 TomyChen(quest) 在 07月16日08时12分编辑过]

地主发表时间: 04/09 15:57

回复: group [group]

论坛用户

看了一段代码，结果发现是被注释掉了的，我晕！～～

B1层发表时间: 04/10 00:26

回复: quest [quest]

版主

被注释的是原来没加多线程的时候用的，用了多线程就注释掉咯

B2层发表时间: 04/10 08:24

回复: TomyChen [quest]

版主

提一下这个帖，虽然代码写得很差...:)